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Differentiation of parametric equation

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In example X=at^3 Y=2at Find dy/dx When we found dx/dt we got 3t^2 from at^3 The value which we got from at^3 t^3=3(t)^2 [video Time Stamp: 05:43] Video Details ------------- Business Mathematics Differential Calculus #3. Key Concepts & Formulae - Part 2

Gurukanta Singh

CA Foundation

★ 17K+

07-Jul-25 11:25

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Answers (4)

What is your exact doubt. what is shown on screen is correct only right?

Sriram Somayajula

Admin

07-Jul-25 14:23

Doubt is from t^3 how we arrived at 3t^2

Thread Starter

Gurukanta Singh

CA Foundation

★ 17K+

07-Jul-25 14:24

Thread Starter

Gurukanta Singh

Doubt is from t^3 how we arrived at 3t^2

it is a rule if t is variable and we have to differentiate t^3 then end outcome is exponent x t power ( exponent - 1) Faculty explained this in prev video at 3.59 I highlighted this in prev forum query response

Sriram Somayajula

Admin

07-Jul-25 14:26

Thanks sir

Thread Starter

Gurukanta Singh

CA Foundation

★ 17K+

07-Jul-25 14:33