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Found relationship between question but not understanding how to solve it
Answers (12)
Dhakshana Dhakshana
Hope u understood if not tell me bru
Pls reply bro is there any other way to solve it
Thread Starter
Samarth KshatriyaPls reply bro is there any other way to solve it
Watch YouTube videos to solve this .This is really easy,since you're a beginner you're finding it difficult.Assume, profit is always given as a % of cost or sales price.If it is 20% of sales price ,we can also say it as 1/5 of sales,then it will be 1/6 of cost.Always take one value extra for cost in denominator
Shankari C
Watch YouTube videos to solve this .This is really easy,since you're a beginner you're finding it difficult.Assume, profit is always given as a % of cost or sales price.If it is 20% of sales price ,we can also say it as 1/5 of sales,then it will be 1/6 of cost.Always take one value extra for cost in denominator
As u tell this is this a topic of foundation or inter
Thread Starter
Samarth KshatriyaAs u tell this is this a topic of foundation or inter
It comes in all levels.Its just a basic
always, Cost + Profit ------------------------ = Sales ------------------------ If given , profit is 33â??% on cost then, Cost(100%) +Profit (33â??). [ Since given profit is 33â?? on cost] ---------------------------- = Sales( 133â??) --------------------------- If given , profit is 33â?? on sales then, Backward solving Sales (100%) - Profit(33â??) [since given profit is 33â?? on sales] --------------------------- Cost (66â??) -------------------------- In your given case , profit is 33â?? on cost while given sales = 80,00,000. So, Cost(100%) +Profit(33â??) --------------------------------------------- = Sales(133â??%) = 80,00,000 --------------------------------------------- So, if 133â??(i.e, sales) is 80l Then 100% (i.e, cost)= 60l(80,00,000Ã?100/133â??) It is simply a unitary methods, very easy if understood concept.