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LR

Maths & Stats

Can u pls solve this problem

Sri kanaga Varshini

CA Final

★ 3K+

16-Nov-20 21:31

306

Answers (2)

A = 1, B = 2 and so on till Z = 26. Then sum of numbers representing 4 alphabets of EXAM = 5 + 24+1 + 13 = 43 Similarly for 5 alphabets of PAPER it is 16 + 1 + 16 + +5 + 18 = 56 EXAM = 39 i.e 43 - 4 alphabets PAPER = 51 i.e 56 - 5 alphabets So PASS will be = 16+1 + 19 + 19 -4 = 51. Answer is 51