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Chain relative
Maths & Stats
answered on 14-Apr-26 13:28
P1/P0 That mean we can divide from Year 1 price index to base and multiply by 100.? [Video Time Stamp: 09:13]
latest answer
The Price Index Number (P₀₁) using the Simple Aggregate Method is calculated by dividing the sum of the prices in the current year (ΣP₁) by the sum of the prices in the base year (ΣP₀), and then multiplying by 100. This gives a measure of the overall change in prices from the base year to the current year
SriVidhya M S
CA Foundation
★ 450
1
71
Doubt
AFM
answered on 13-Apr-26 20:30
Here, the dividend is paid on face value, but we are taking the percentage of the dividend on the index. What is the reason? [Video Time Stamp: 16:36]
latest answer
Dividend when stated as paid as as percentage then we consider it on FV When stated as yield we take it as percentage of market value This is standard convention in the market
pavan kumar
CA Final
★ 2K+
1
43
Doubt
AFM
answered on 13-Apr-26 20:35
1. In the above question, the lot size is not mentioned. It says 1 future contract is for the delivery of 50 times the index. 2. Why are we choosing the BSE index for the computation of future price instead of choosing the value of the portfolio, which we did in the previous question? [Video Time Stamp: 15:12]
latest answer
In previous question they asked us to find out value of stock futures Here they have asked us to hedge the portfolio and that hedging cannot happen by entering to portfolio futures by using stock index futures . Here we use index futures adjusting their quantity to ensure beta of portfolio is same as beta of futures
pavan kumar
CA Final
★ 2K+
1
57
FOR CA FINAL AFM IMPORTANT QUESTIONS LIST - UNDER Derivative Analysis Under Options they have mentioned Question no. 38,39 but the p600+ have only questions up to 37 where does the question 38 and 39 come from?..
AFM
answered on 13-Apr-26 18:32
FOR CA FINAL AFM IMPORTANT QUESTIONS LIST - UNDER Derivative Analysis Under Options they have mentioned Question no. 38,39 but the p600+ have only questions up to 37 where does the question 38 and 39 come from?..
latest answer
Thank you 👍
Lingesh Elumalai
CA Final
★ 300
3
60
Doubt
AFM
answered on 13-Apr-26 15:00
1. Can we sell some of our stocks at a time in the cash market? [Video Time Stamp: 19:24]
latest answer
Yes
pavan kumar
CA Final
★ 2K+
1
50
Doubt
AFM
answered on 13-Apr-26 12:17
1.What happens, If the theoretical price is higher than the future price in this example. 2.We are considering bullish every time. What happens if it is a bearish market.
latest answer
Those scenarios are also considered in subsequent examples. Of Theoretical price is higher then Buy Futures in market as they are cheaper than theoretical price Buy cheap sell costly
pavan kumar
CA Final
★ 2K+
1
50
GST CALCULATION
Accountancy
answered on 13-Apr-26 09:31
44,800 is not just the original price — it is: 100% (original price) + 12% (tax) = 112% That means: ₹44,800 = 112 parts You want to know 100 parts Simple method: If 112 parts = ₹44,800 Then 1 part = 44,800 ÷ 112 = 400 So 100 parts = 400 × 100 = ₹40,000 Tax: 12 parts = 400 × 12 = ₹4,800 Can I apply like this? [Video Time Stamp: 18:03]
latest answer
Yes, you can apply like that.
SriVidhya M S
CA Foundation
★ 450
1
67
Permutations and combinations
Maths & Stats
answered on 14-Apr-26 13:27
1. The results of 8 matches (win, lose or draw) are to be predicted. The number of different forecasts containing exactly 6 correct results is? 2. The number of different factors the number 75,600 has is 3. The number of 4 digit numbers formed with the digits 1, 1, 2, 2, 3, 4
latest answer
To find the number of 4-digit numbers that can be formed using the digits 1,1,2,2,3,4, we need to consider the repetitions of the digits. The digits available are two 1's, two 2's, one 3, and one 4. We will use the formula for permutations of multiset: P(n;n 1 ,n 2 ,...,n k)= n!/ (n 1 !⋅n 2 !⋯n k!) where n is the total number of items, and n 1 ,n 2,...,n k are the counts of each distinct item. In our case, we can choose 4 digits from the available digits, and we will consider different cases based on the repetitions of the digits. Case 1: All digits are different (1, 2, 3, 4) We can choose 4 digits from {1, 2, 3, 4}. The number of arrangements is: P(4;1,1,1,1)= 4! / (1!⋅1!⋅1!⋅1! )=24 Case 2: One digit appears twice, and two other digits are different. Possible combinations: (1, 1, 2, 3), (1, 1, 2, 4), (1, 1, 3, 4), (2, 2, 1, 3), (2, 2, 1, 4), (2, 2, 3, 4). For each combination, the number of arrangements is: P(4;2,1,1)= 4! / ( 2!⋅1!⋅1!) =12 Total for this case: 6×12=72. Case 3: Two digits appear twice (1, 1, 2, 2) The number of arrangements is: P(4;2,2)= 4! (2!⋅2!) =6 Total Count Adding all cases together:24+72+6=102
Mrittika
CA Foundation
★ 0
3
79
Permutations and combinations
Maths & Stats
answered on 20-Apr-26 11:06
1. The number of arrangements of 10 different things taken 4 at a time in which one particular thing always occurs is 2. If nCr-1 =56 , nCr =28 and nCr+1=8 then r is ?
latest answer
We use Combination for selecting the remaining 3 from 9 because the order of selection doesn't matter ,we just care about which items are chosen, not the sequence of choosing them. Once selected, we multiply by 4! to arrange all 4 items in order, since placement does matter.
Mrittika
CA Foundation
★ 0
4
90
CFA
answered on 12-Apr-26 19:57
sir can you share me the link of pdf of kaplan that you are using class for explanation.. [Video Time Stamp: 17:02]
latest answer
Equity investments
Sai Kiran
CFA L1
★ 5
1
74