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Please explain the 2 second step. I can't understand how the base and the log number changed.
Answers (5)
Thread Starter
Vijay KSorry for not uploading the picture.
These are all fundamental properties of logarithms - pls check the chapter - they have ben explained
Here the logarithmic function is at the power of some variable. That's why I can't get it. I have checked the class but I couldn't find the class for logarithmic function on the power a variable. I am sorry sir. Can you please explain how to change the logarithmic function at the power of variable.
Thread Starter
Vijay KHere the logarithmic function is at the power of some variable. That's why I can't get it. I have checked the class but I couldn't find the class for logarithmic function on the power a variable. I am sorry sir. Can you please explain how to change the logarithmic function at the power of variable.
First step, we use formula of a^(m -n) = a^m / a^n Second step formula is derived from: Let x=a^logb and y=b^loga. Then logx=loga. logb =logy. So, x=y.
Sahibdeep Singh
First step, we use formula of a^(m -n) = a^m / a^n Second step formula is derived from: Let x=a^logb and y=b^loga. Then logx=loga. logb =logy. So, x=y.
Now understood sir. Thank you for the help.