Equations

answered on 28-Aug-23 13:43

Please help me find the answer

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Ans = 9

Taniya Thakur

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Equations

answered on 28-Aug-23 13:12

Please help me solve this question!

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Yeah! Okay got it thanks

Taniya Thakur

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Time Value of Money

answered on 28-Aug-23 06:41

I am not able solve the Question Can you please explain the solution

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This can be done by assuming interest rate as x and solving or take a number from the options preferrbaly between 3.46 and 3.6 i.e 3.5% and substituting and solving for it If we assume x as interest rate then 725 * x%* 12/12 + 362.50 *2x*4/12 = 33.50 725x% + 724x%/3 = 33.50 2175x% +725x%=100.5 2900x% = 100.5 x% = 100.5/2900 x% = 3.4655%

Ab Devliear

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Statistics

answered on 18-Aug-23 21:25

Is correlation and regression depend on any other chapter like after complete that chapter can understand this chapter???

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In statistics start preparing the chapters in the order it is given in Study Material It will help u in understanding the concepts better

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Permutation

answered on 14-Sep-23 20:08

If all the latters of the word 'AGAIN' be arranged as in a dictionary, what is the fiftieth word? (a) NAAGI (b) NAAIG (c) GIAAN (d) NAGAI

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Yes this is right

Nakshathra Baiju

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Combination

answered on 09-Aug-23 10:28

Find the number of combinations for the following words taking 4 at a time. 6) COMBINATION (ii) COLLEGE (iv) MATHEMATICS (iii) COMMERCE (v) EXAMINATION (vi) MORADABAD (vii) PROPORTION (a) 136, 18, 26, 136, 136, 53, 41 Ac) 136, 18, 26, 136, 136, 41, 53 (d) none of these (b) 41, 136, 18, 26, 136, 53, 136

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Answer is none of these Consider Examination It has letters E, X, A, M, I, N, T, O where A, I, N are repeated twice. So, four letter word may consist of (i) 2 alike letters of one kind and 2 alike of letter of the second kind. (ii) All different (iii) 2 alike and 2 distinct letter So in (i) There are three sets of alike letters, namely AA, NN, II. Out of these three sets, two can be selected in 3C2 ways. So, there are 3C2 groups, each containing 4 letters out of which two are alike letters of one kind and two are like letters of the second kind. Now, 4 letters in each group can be arranged in 4!2!×2! Therefore, the total number of four letters words are 3C2×4!2!×2!=3×6=18 Since, The total number of letter =11 Similar way, (ii) All different i.e. 8C4×4!=8!4! As selecting 4 out of 8 different letters is 8C4 Arrangement of these 4 are done by 4! Thus, 8!4!=8×7×6×5×4!4!=56×30=1680 (iii) 2 alike and 2 distinct letter: 3C1×7C2=3×7×6×5!5!×2=3×7×62=378 [ Since, nCr=nCn−r] ∴ Total number of ways in which 4 letter words are formed = 1680 +378 +18 +378=2454 ways. Consider PROPORTION We have P & R 2 times, O 3 times and other letters T, I, and N once 1. Words with four distinct letters. We have 6 letters all total (I,N,P,R,O and T) so we can arrange this letter in 6 C4 ×4!=360 ways 2. Words with exactly a letter repeated twice. We have P, R and O repeating itself. Now one of this three letter can be choose in 3 C1 =3 ways The other two distinct letters can be selected in 5 C2 =10 ways. Now each combination can be arranged in 2!4! =12 ways. So total number of such words 3×10×12= 360 ​ 3. Words with exactly two distinct letters repeated twice Two letters out of the three repeating letters P, R and O can be selected in 3 C2 =3 ways. Now each combination can be arranged in 2!×2!4! =6 So, total number of such words =3×6= 18 ​ 4. Words with exactly a letter repeated thrice We have one portion for this as our main letter that is O. Now we have to select 1 letter out of the 5 remaining options so number of ways to select this 5 C1 =5 ways Now each combination can be arranged in 3!4! =4 So, total number of such words =5×4= 20 ​So, all possible number of arrangements =360+360+18+20=758 ways

Nakshathra Baiju

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Equations

answered on 25-Jul-23 23:10

Can anyone please solve this question? I feel the answer is some where wrong

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Thankyou so much

Divinne Fiona

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Time value of money Compound interest

answered on 19-Jul-23 20:33

In que. 13) the 39.4 and 19.4 are also rates knw...like℅ or they are no. Of ppl? If 39.4-19.4=20 If they are like ℅ why don't we take 20℅ in formula?

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per thousand not %

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Maths

answered on 16-Aug-23 07:51

There is a confusion in this question. Anyone can help me.

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Thanks

Sourav S V

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Practice

answered on 03-Jul-23 17:40

Other than study material which sums have to practice

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For Paper-3 - Maths, LR and Stats, you may follow these tips: - Be quick in solving - 1 min for 1 question - If it takes more time, leave that question and come back again after completing all other remaining questions - Use shortcuts - Use option wise verification method, i.e., sometimes instead of solving, substitute the answer in the question and check which is the right answer. This helps in saving time in exam. - Learn some calculator tricks - Solve easy questions first - Lengthy and time taking questions can be kept for the last - Try to solve maximum questions - If you are 75 to 80% sure about the answer, you may attempt it. - If you are very much confused about the answer, you may leave it to avoid negative marking. - Before the exam, get more practice by solving MTPs, RTPs and PYQs. - 13-14 marks come from Time value of money. So, study that chapter thoroughly. - LR is very easy. You can complete it within 2 days and it is very scoring. So, have a good grip on that. Then cover statistics and maths. - Solve the exercise questions, additional questions "MULTIPLE" times to get absolute clarity. Do your best and leave the rest to God. All the best.

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