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Permutations and Combinations

Maths & Stats

Anyone explain 15th sum

Sr the Unique

CA Inter

★ 10

03-Jun-23 12:53

188

Answers (2)

Correct answer is option (a) 24 There are 5 speakers - A, B, C, D & E. A will speak always before B. So, we will consider these two speakers A and B as one group. And consider other 3 speakers as individual groups. So, there are 4 groups that have to be arranged in a row. So, it can be done in 4P4 different ways. Hence, The no. of ways in which A will speak before B = 4P4 = 4 x 3 x 2 x 1 = 24