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Three coin are tossed simultaneously. Find the probability of getting { ( H,H,H),(H,H,T),(H,T,H),(T,H,H) (T,T,T),(T,T,H),(T,H,T),(H,T,T)} heads are the two extremes. A)2/8. B)6/8. C)1/8. D)4/8
Answers (2)
Thread Starter
Sejal ShivaniI think answer is D)4/8 Am I right or wrong?
Can you please clarify the question - probability of getting heads....?