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Can any one solve this sum and send solution
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Best Answer
a) 32/99 Case 1: Red ball is picked from Bag 1 Probability = 5/9 Bag 2 will now have 4 red and 7 black. A red can be picked with probability = 4/11 Case 1 probability is 5/9 x 4/11 = 20/99 Case 2: Black ball is picked from Bag 1 Probability = 4/9 Bag 2 will now have 3 red and 8 black. A red can be picked with probability = 3/11 Case 2 probability is 4/9 x 3/11 = 12/99 So, possibility of red from second bag = 20/99 + 12/99 = 32/99
