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If a:b=n,d, and b:c = n, d, then a) a:b:c = n, d, :n :d2:d, :d, c) a:bc = n, n, d, n, d, d, b) a:b:c = n, d, n, d,id d) None

Jagruthi Yadav

CA Inter

★ 5K+

09-Mar-21 21:24

425

Answers (9)

Option C is correct

sai t

CA Foundation

★ 2K+

10-Mar-21 05:06

Could you be more specific with the question and the solution how the answer arrived? Please share the image of the question and the answer, so that we can look into it and help you in resolving your query.

Lavanya Chitturi

CA Inter

★ 895

10-Mar-21 17:04

Sum number 31.

Thread Starter

Jagruthi Yadav

CA Inter

★ 5K+

10-Mar-21 20:04

sai t

Option C is correct

Yeah bt how can u give me some explanation

Thread Starter

Jagruthi Yadav

CA Inter

★ 5K+

10-Mar-21 20:05

Thread Starter

Jagruthi Yadav

Yeah bt how can u give me some explanation

Here it is..

Meda Jeevansai

CA Inter

★ 20K+

10-Mar-21 20:35

Thread Starter

Jagruthi Yadav

Yeah bt how can u give me some explanation

Make value of B same in both ratios by multiplying with a number and then combine all ratios ie A:B = n1:d1 multiply by n2 it will become A:B = n1n2:d1n2 same way B:C is n2:d2 multiply by d1 it will become n2d1:d2d1 Now combine both ratios as B value is common in both ratios A:B:C = n1n2: d1n2:d1d2