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If a:b=n,d, and b:c = n, d, then a) a:b:c = n, d, :n :d2:d, :d, c) a:bc = n, n, d, n, d, d, b) a:b:c = n, d, n, d,id d) None

CA Foundation

2K+

09-Mar-21 21:24

37

Option C is correct

sai t

CA Foundation

295

10-Mar-21 05:06

Could you be more specific with the question and the solution how the answer arrived? Please share the image of the question and the answer, so that we can look into it and help you in resolving your query.

Lavanya Chitturi

Moderator

10-Mar-21 17:04

Sum number 31.

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dfe4bf1a-9485-4218-b78d-95cf0ef0dc9c.jpg

CA Foundation

2K+

10-Mar-21 20:04

Option C is correct

Yeah bt how can u give me some explanation

CA Foundation

2K+

10-Mar-21 20:05

Yeah bt how can u give me some explanation

Here it is..

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IMG_20210310_203512.jpg

Meda Jeevansai

CA Foundation

11K+

10-Mar-21 20:35

Yeah bt how can u give me some explanation

Make value of B same in both ratios by multiplying with a number and then combine all ratios ie A:B = n1:d1 multiply by n2 it will become A:B = n1n2:d1n2 same way B:C is n2:d2 multiply by d1 it will become n2d1:d2d1 Now combine both ratios as B value is common in both ratios A:B:C = n1n2: d1n2:d1d2

Sriram Somayajula

10-Mar-21 20:38

Thank you sir ð???

CA Foundation

2K+

10-Mar-21 21:06

Here it is..

Thanks sir ð???

CA Foundation

2K+

10-Mar-21 21:06

Thanks sir ð???

I'm not sir, I'm student like you!

Meda Jeevansai

CA Foundation

11K+

10-Mar-21 21:11

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