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Chapter 9

Maths & Stats

answered on 18-Nov-23 02:57

44) ZDRCVF please explain the sum

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I think you have the double with regard to Logical reasoning kindly elaborate ur question

Kumari Jayanthi

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THEORETICAL DISTRIBUTIONS

Maths & Stats

answered on 22-Nov-23 09:48

Anyone please explain me the answer/logic behind this sum (33rd sum)?

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Ok..Thank you sir.

Sr the Unique

CA Inter

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4

180

Integration by parts

Maths & Stats

answered on 06-Nov-23 10:45

Partial fraction ..........,........ .......................... . ............................

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Pfa the soln

CHANCHAL Gaur

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126

Probability

Maths & Stats

answered on 21-Oct-23 14:50

When we should add and multiply to get the values of probability????

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Or - Add And - Multiply

SRIHARI K U [XI-D]

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Chapter 9

Maths & Stats

answered on 27-Oct-23 10:28

40) If MEKLF is coded as 91782 and LLLJK as 88867, how can IHJED be coded as? 42) If GOLD is written as IQNF, how WIND can be written as code? Please give a clear explanation in the step-by-step sir.

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E is 1 & M is 9 so D is 26 so answer for IHJED is 546126

Kumari Jayanthi

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181

Chapter 9

Maths & Stats

answered on 19-Oct-23 17:16

27) 8, 28,116,584? Please explain set-by-set sir.

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Thank you

Kumari Jayanthi

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Chapter 9

Maths & Stats

answered on 19-Oct-23 17:15

7, 26, 63,124,215,?, 511 Please explain set-by-set sir.

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Thank you

Kumari Jayanthi

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Jaynthi

Maths & Stats

answered on 19-Oct-23 07:44

2, 3, 3, 5, 10, 13, 39,?, 172,177 Please explain this sum, sir.

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before putting ur query.... Kindly self.. do..it will get ans... once u get the ans Once if you got. You will be motivated to solve other types as well... However Ans for the above .. is 2+1=3 3*1=3 3+2=5 5*2=10 10+3=13 13*3=39 39+4=43{ Missing figure} 43*4=172 172+5=177

Kumari Jayanthi

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SetC ch. 15

Maths & Stats

answered on 15-Oct-23 12:04

Q. 23,.............................. Probability

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Ya we can use modulus as well..👍

CHANCHAL Gaur

CA Foundation

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146

Jayanthi

Maths & Stats

answered on 14-Oct-23 08:11

If A: B= 3:2 and B: C 3:5, then A: B: C is Please explain this sum, sir.

latest answer

A/B=3/2 and B/C=3/5 2A=3B,5B=3C multiply with 5, multiply with 3 both sides 10A=15B,15B=9C 10A=15B=9C

Kumari Jayanthi

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