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Chapter 9

Maths & Stats

answered on 18-Nov-23 02:57

44) ZDRCVF please explain the sum

latest answer

I think you have the double with regard to Logical reasoning kindly elaborate ur question

Kumari Jayanthi

Kumari Jayanthi

CA Foundation

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THEORETICAL DISTRIBUTIONS

Maths & Stats

answered on 22-Nov-23 09:48

Anyone please explain me the answer/logic behind this sum (33rd sum)?

latest answer

Ok..Thank you sir.

Sr the Unique

Sr the Unique

CA Inter

10

4

180

Integration by parts

Maths & Stats

answered on 06-Nov-23 10:45

Partial fraction ..........,........ .......................... . ............................

latest answer

Pfa the soln

CHANCHAL Gaur

CHANCHAL Gaur

CA Foundation

115

2

126

Probability

Maths & Stats

answered on 21-Oct-23 14:50

When we should add and multiply to get the values of probability????

latest answer

Or - Add And - Multiply

SRIHARI K U [XI-D]

SRIHARI K U [XI-D]

CA Foundation

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Chapter 9

Maths & Stats

answered on 27-Oct-23 10:28

40) If MEKLF is coded as 91782 and LLLJK as 88867, how can IHJED be coded as? 42) If GOLD is written as IQNF, how WIND can be written as code? Please give a clear explanation in the step-by-step sir.

latest answer

E is 1 & M is 9 so D is 26 so answer for IHJED is 546126

Kumari Jayanthi

Kumari Jayanthi

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Chapter 9

Maths & Stats

answered on 19-Oct-23 17:16

27) 8, 28,116,584? Please explain set-by-set sir.

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Thank you

Kumari Jayanthi

Kumari Jayanthi

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Chapter 9

Maths & Stats

answered on 19-Oct-23 17:15

7, 26, 63,124,215,?, 511 Please explain set-by-set sir.

latest answer

Thank you

Kumari Jayanthi

Kumari Jayanthi

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Jaynthi

Maths & Stats

answered on 19-Oct-23 07:44

2, 3, 3, 5, 10, 13, 39,?, 172,177 Please explain this sum, sir.

latest answer

before putting ur query.... Kindly self.. do..it will get ans... once u get the ans Once if you got. You will be motivated to solve other types as well... However Ans for the above .. is 2+1=3 3*1=3 3+2=5 5*2=10 10+3=13 13*3=39 39+4=43{ Missing figure} 43*4=172 172+5=177

Kumari Jayanthi

Kumari Jayanthi

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SetC ch. 15

Maths & Stats

answered on 15-Oct-23 12:04

Q. 23,.............................. Probability

latest answer

Ya we can use modulus as well..👍

CHANCHAL Gaur

CHANCHAL Gaur

CA Foundation

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3

146

Jayanthi

Maths & Stats

answered on 14-Oct-23 08:11

If A: B= 3:2 and B: C 3:5, then A: B: C is Please explain this sum, sir.

latest answer

A/B=3/2 and B/C=3/5 2A=3B,5B=3C multiply with 5, multiply with 3 both sides 10A=15B,15B=9C 10A=15B=9C

Kumari Jayanthi

Kumari Jayanthi

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