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Quartile

Maths & Stats

answered on 08-Jun-20 05:50

If we want to find 2nd quartile what we use n+2/4 or (n+1/4)2

latest answer

Tqq.... sister

Jashwanth S

Jashwanth S

CMA Inter

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4

459

Geometric mean

Maths & Stats

answered on 06-Jun-20 20:31

Please solve this question

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Ok sir

Priyanka Saini

Priyanka Saini

CA Foundation

12K+

3

462

Class boundary and class interval

Maths & Stats

answered on 07-Jun-20 17:22

Sir once say what is class boundary and class interval with one example table And say what is caption and box head also

latest answer

Class boundary is the difference between the upper class limit of the class and the lower class limit of the next class in the sequence.

Jashwanth S

Jashwanth S

CMA Inter

2K+

7

520

MCT

Maths & Stats

answered on 29-May-20 18:42

Can any one explain how to find the class boundaries incaes of frequency distribution on median ?..

latest answer

Did you go through the video and still could not understand?

Balaji R

Balaji R

CA Inter

6K+

1

490

MCT

Maths & Stats

answered on 31-May-20 09:51

How to find median value in case of the following questions? X 3. 5. 7. 9. 11. 13 Frequency. 4. 3. 5. 2. 3. 3

latest answer

Using cumulative frequency.

Balaji R

Balaji R

CA Inter

6K+

1

442

f pqr = ax ,qrs= ay and rsp= az , then find the value of (pqrs)1/2

Maths & Stats

answered on 31-May-20 10:43

f pqr = ax ,qrs= ay and rsp= az , then find the value of (pqrs)1/2 solution please

latest answer

Solved

Janith Salian

Janith Salian

CA Foundation

0

1

3K+

Central tendency

Maths & Stats

answered on 25-May-20 12:17

Question no.6,7,8

latest answer

What is your doubt?

Priyanka Saini

Priyanka Saini

CA Foundation

12K+

1

565

Central tendency

Maths & Stats

answered on 25-May-20 12:17

Question no.4,5

latest answer

Pls share the answer which you worked out.

Priyanka Saini

Priyanka Saini

CA Foundation

12K+

3

502

???

Maths & Stats

answered on 18-May-20 07:16

How to do this problem?

latest answer

Assume 100 KG of mixed quantity is the output. In that output, assume qty of tea worth Rs.20 is X kg. Then Qty of Rs.28 worth tea is 100kg-X KG . Solve the equation 20 * X + 28 * (100-X) = 25 * 100. You will X as 37.5 and 100-X as 62.5. So ratio is 37.5:62.5 i.e 3:5

Vignesh Sp

Vignesh Sp

CA Foundation

0

2

526

Ratii

Maths & Stats

answered on 01-Jun-20 08:54

Question 4

latest answer

14=21k/2 k=28/21 or 4/3 y+z=7k or 28/3 x=14-28/3 = 14/3 Y = 10/3 Z= 6

hazil ameer

hazil ameer

CA Inter

2K+

8

546


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